As a supplier dealing with a wide range of products related to the code 61219329739, I often find myself delving into various mathematical and business - related concepts. Today, let's explore the mathematical question: "What is the sum of all positive integers less than 61219329739 that are divisible by 3?"


Understanding the Problem
To find the sum of all positive integers less than a given number (N = 61219329739) that are divisible by 3, we first need to understand the nature of these numbers. The positive integers divisible by 3 form an arithmetic sequence. An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms is constant. In the case of positive integers divisible by 3, the sequence is (3,6,9,\cdots) and the common difference (d = 3).
The first term (a_1) of the sequence of positive integers divisible by 3 is 3. We need to find the last term (a_n) of the sequence that is less than 61219329739.
We know that the (n) - th term of an arithmetic sequence is given by the formula (a_n=a_1+(n - 1)d), where (a_1) is the first term, (d) is the common difference, and (n) is the number of terms.
Let (a_n<61219329739). Since (a_n = 3+(n - 1)\times3=3n), we set (3n<61219329739). Solving for (n), we get (n<\frac{61219329739}{3}=20406443246.33\cdots). Since (n) is an integer, the largest (n) for which (a_n<61219329739) is (n = 20406443246).
The Sum Formula for Arithmetic Sequences
The sum (S_n) of the first (n) terms of an arithmetic sequence is given by the formula (S_n=\frac{n(a_1 + a_n)}{2}), where (a_1) is the first term, (a_n) is the (n) - th term, and (n) is the number of terms.
We know that (a_1 = 3), (n = 20406443246), and (a_n=a_1+(n - 1)d=3+(20406443246 - 1)\times3=3\times20406443246)
Substituting these values into the sum formula:
[
\begin{align*}
S_n&=\frac{n(a_1 + a_n)}{2}\
&=\frac{20406443246\times(3+3\times20406443246)}{2}\
&=\frac{20406443246\times3\times(1 + 20406443246)}{2}\
&=\frac{3\times20406443246\times20406443247}{2}\
\end{align*}
]
Let's calculate this value. (20406443246\times20406443247=(20406443246.5 - 0.5)\times(20406443246.5+0.5))
Using the difference - of - squares formula ((a - b)(a + b)=a^{2}-b^{2}), where (a = 20406443246.5) and (b = 0.5), we have (20406443246\times20406443247=20406443246.5^{2}-0.25)
(20406443246.5^{2}=(20406443246+\ 0.5)^{2}=20406443246^{2}+2\times20406443246\times0.5 + 0.25)
[
\begin{align*}
S_n&=\frac{3}{2}\times(20406443246\times20406443247)\
&=\frac{3}{2}\times(20406443246^{2}+20406443246)\
\end{align*}
]
We can also calculate directly:
[
\begin{align*}
S_n&=\frac{3\times20406443246\times20406443247}{2}\
&=\frac{3\times(20406443246\times(20406443246 + 1))}{2}\
&=\frac{3\times(20406443246^{2}+20406443246)}{2}\
\end{align*}
]
(20406443246\times20406443246=20406443246^{2}=416423713947437775076)
(20406443246\times1 = 20406443246)
(20406443246^{2}+20406443246=416423713947437775076+20406443246=416423715988082107522)
(S_n=\frac{3\times416423715988082107522}{2}=624635573982123161283)
Business Implications
In the business world, mathematical concepts like this can have various applications. For instance, when dealing with inventory management, if we have a set of products with a price or quantity that is related to multiples of 3 (say, we sell products in packs of 3), understanding the sum of these values can help in forecasting revenue, estimating stock levels, and making pricing decisions.
As a supplier of products related to 61219329739, I am always looking for ways to optimize my business processes. Mathematical analysis can help in predicting trends, understanding customer demand patterns, and streamlining operations.
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Conclusion
In conclusion, the sum of all positive integers less than 61219329739 that are divisible by 3 is 624635573982123161283. This mathematical exercise not only enriches our knowledge but also has practical applications in the business world.
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References
- "Arithmetic Sequences and Series" in standard high - school mathematics textbooks.
- Business management books on inventory management and data analytics.
